Python and successive approximation
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I was doing some work in the yard and I wanted to know the smallest circle that would fit around a 4x6 inch post. Of course, just as a 2x4 is not 2 inches by 4 inches, a 4x6 post (what they call its "nominal" dimensions) is actually 3.5 inches by 5.5 inches, so this smallest circle has as its diameter the diagonal of that 3.5x5.5-inch rectangle. Pythagoras tells us that will be the square root of the sum of 3.5 squared and 5.5 squared. At the time, I only had my cell phone, which has a calculator with only basic math operations, so how do you get the square root of 42.5?
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